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《SQL反模式》 阅读笔记

反模式分类

  • 逻辑数据库设计反模式
  • 物理书库设计反模式
  • 查询反模式
  • 应用程序开发反模式

反模式分解

  • 目的
  • 反模式
  • 如何识别反模式
  • 合理使用反模式
  • 解决方案

ER 图示例

ER 图示例

范例数据库

SERIAL 是 MySQL 中 BIGINT UNSIGNED NOT NULL AUTO_INCREMENT UNIQUE 的别名

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CREATE TABLE IF NOT EXISTS Accounts (
account_id SERIAL PRIMARY KEY,
account_name VARCHAR(20),
first_name VARCHAR(20),
last_name VARCHAR(20),
email VARCHAR(100),
password_hash CHAR(64),
portrait_image BLOB,
hourly_rate NUMERIC(9,2)
);

CREATE TABLE IF NOT EXISTS BugStatus (
`status` VARCHAR(20) PRIMARY KEY
);

CREATE TABLE IF NOT EXISTS Bugs (
bug_id SERIAL PRIMARY KEY,
date_reported DATE NOT NULL,
summary VARCHAR(80),
description VARCHAR(1000),
resolition VARCHAR(1000),
reported_by BIGINT UNSIGNED NOT NULL,
assigned_to BIGINT UNSIGNED,
verified_by BIGINT UNSIGNED,
`status` VARCHAR(20) NOT NULL DEFAULT 'NEW',
priority VARCHAR(20),
hours NUMERIC(9,2),
FOREIGN KEY (reported_by) REFERENCES Accounts(account_id),
FOREIGN KEY (assigned_to) REFERENCES Accounts(account_id),
FOREIGN KEY (verified_by) REFERENCES Accounts(account_id),
FOREIGN KEY (`status`) REFERENCES BugStatus(`status`)
);

CREATE TABLE IF NOT EXISTS Comments (
comment_id SERIAL PRIMARY KEY,
bug_id BIGINT UNSIGNED NOT NULL,
author BIGINT UNSIGNED NOT NULL,
comment_date DATETIME NOT NULL,
comment TEXT NOT NULL,
FOREIGN KEY (bug_id) REFERENCES Bugs(bug_id),
FOREIGN KEY (author) REFERENCES Accounts(account_id)
);

CREATE TABLE IF NOT EXISTS Screenhots (
bug_id BIGINT UNSIGNED NOT NULL,
image_id BIGINT UNSIGNED NOT NULL,
screenshot_image BLOB,
caption VARCHAR(100),
PRIMARY KEY (bug_id,image_id),
FOREIGN KEY (bug_id) REFERENCES Bugs(bug_id)
);

CREATE TABLE IF NOT EXISTS Tags (
bug_id BIGINT UNSIGNED NOT NULL,
tag VARCHAR(20) NOT NULL,
PRIMARY KEY (bug_id,tag),
FOREIGN KEY (bug_id) REFERENCES Bugs(bug_id)
);

CREATE TABLE IF NOT EXISTS Products (
product_id SERIAL PRIMARY KEY,
product_name VARCHAR(50) NOT NULL
);

CREATE TABLE IF NOT EXISTS BugsProducts (
bug_id BIGINT UNSIGNED NOT NULL,
product_id BIGINT UNSIGNED NOT NULL,
PRIMARY KEY (bug_id,product_id),
FOREIGN KEY (bug_id) REFERENCES Bugs(bug_id),
FOREIGN KEY (product_id) REFERENCES Products(product_id)
);